ID 21387

Conditional interpretation: #IF without corresponding #ENDIF programmed.

Description

A “Conditional interpretation” was programmed in incomplete syntax. An #IF must be terminated by an #ENDIF.

Example:

Wrong:

N01   P1=0

#IF P1==1

N10     G00 X0 Y0 Z0

:

N25     G01 X100 Y0 Z0 F1000

:

N1000 M30

Correct:

N01   P1=0

#IF P1==1

N10     G00 X0 Y0 Z0

:

N25     G01 X100 Y0 Z0 F1000

#ENDIF

:

N1000 M30

Response

Class

2

Abort NC program processing.

Solution

Class

3

Check and modify the program flow sequence. Complete the #IF/ #ENDIF instruction or delete the #IF.

Error type

1, Error message from NC program.